\begin{document}$ \phi,\rho $\end{document} mesons \begin{document}$ M_{\phi,\rho}(\Omega)\simeq M_{\phi,\rho}(\Omega=0)-s_{z}\Omega $\end{document}. This behavior contributes to the spin alignment of vector mesons \begin{document}$ \phi,\rho $\end{document} in an equilibrium medium and naturally explains the negative deviation of \begin{document}$ \rho_{00}-1/3 $\end{document} for vector mesons. Incidentally, the positive deviation of \begin{document}$ \rho_{00}-1/3 $\end{document} under the magnetic field can also be easily understood from quark dynamics."> Spin alignment of vector mesons from quark dynamics in a rotating medium -
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