\begin{document}$ s_z = 0,\pm 1 $\end{document} of a vector meson under rotation exhibits a very simple mass splitting relation \begin{document}$ m_{\rho}^{s_z}(\omega) = m_\rho(\omega = 0)-\omega s_z $\end{document}, similar to the Zeeman splitting of a charged meson under magnetic fields. Furthermore, the mass of the spin component \begin{document}$ s_z = 1 $\end{document} of vector meson ρ decreases linearly with ω and reaches zero at \begin{document}$ \omega_c = m_\rho(\omega = 0) $\end{document}, which indicates that the system will develop \begin{document}$ s_z = 1 $\end{document} vector meson condensation and the system will be spontaneously spin-polarized under rotation."> Mass splitting of vector mesons and spontaneous spin polarization under rotation -
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